1/3x+3/4x=39

Solution for 1/3x+3/4x=39 equation:

1/3x+3/4x=39

We move all terms to the left:

1/3x+3/4x-(39)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R



Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R


We calculate fractions


4x/12x^2+9x/12x^2-39=0

We multiply all the terms by the denominator


4x+9x-39*12x^2=0

We add all the numbers together, and all the variables

13x-39*12x^2=0

Wy multiply elements

-468x^2+13x=0

a = -468; b = 13; c = 0;
Δ = b2-4ac
Δ = 132-4·(-468)·0
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-13}{2*-468}=\frac{-26}{-936}
=1/36
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+13}{2*-468}=\frac{0}{-936}
=0
$