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1/3x+4+2x+2/3=22/3+1
We move all terms to the left:
1/3x+4+2x+2/3-(22/3+1)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
2x+1/3x+4+2/3-(22/3+1)=0
We get rid of parentheses
2x+1/3x+4-1+2/3-22/3=0
We calculate fractions
2x+4-1=0
We add all the numbers together, and all the variables
2x+3=0
We move all terms containing x to the left, all other terms to the right
2x=-3
x=-3/2
x=-1+1/2
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