1/3x+40=58

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Solution for 1/3x+40=58 equation: 



1/3x+40=58

We move all terms to the left:

1/3x+40-(58)=0



Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R



We add all the numbers together, and all the variables

1/3x-18=0

We multiply all the terms by the denominator


-18*3x+1=0

Wy multiply elements

-54x+1=0

We move all terms containing x to the left, all other terms to the right

-54x=-1

x=-1/-54

x=1/54

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