1/3x+4=1/8x

Solution for 1/3x+4=1/8x equation:

1/3x+4=1/8x

We move all terms to the left:

1/3x+4-(1/8x)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R



Domain of the equation: 8x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

1/3x-(+1/8x)+4=0

We get rid of parentheses

1/3x-1/8x+4=0

We calculate fractions


8x/24x^2+(-3x)/24x^2+4=0

We multiply all the terms by the denominator


8x+(-3x)+4*24x^2=0

Wy multiply elements

96x^2+8x+(-3x)=0

We get rid of parentheses

96x^2+8x-3x=0

We add all the numbers together, and all the variables

96x^2+5x=0

a = 96; b = 5; c = 0;
Δ = b2-4ac
Δ = 52-4·96·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-5}{2*96}=\frac{-10}{192}
=-5/96
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+5}{2*96}=\frac{0}{192}
=0
$