1/3x+4=1x-2

Solution for 1/3x+4=1x-2 equation:

1/3x+4=1x-2

We move all terms to the left:

1/3x+4-(1x-2)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R


We add all the numbers together, and all the variables

1/3x-(x-2)+4=0

We get rid of parentheses

1/3x-x+2+4=0

We multiply all the terms by the denominator


-x*3x+2*3x+4*3x+1=0

Wy multiply elements

-3x^2+6x+12x+1=0

We add all the numbers together, and all the variables

-3x^2+18x+1=0

a = -3; b = 18; c = +1;
Δ = b2-4ac
Δ = 182-4·(-3)·1
Δ = 336
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{336}=\sqrt{16*21}=\sqrt{16}*\sqrt{21}=4\sqrt{21}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-4\sqrt{21}}{2*-3}=\frac{-18-4\sqrt{21}}{-6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+4\sqrt{21}}{2*-3}=\frac{-18+4\sqrt{21}}{-6}
$