1/3x+4=3/2x+

Solution for 1/3x+4=3/2x+ equation:

1/3x+4=3/2x+

We move all terms to the left:

1/3x+4-(3/2x+)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R



Domain of the equation: 2x+)!=0

x∈R


We add all the numbers together, and all the variables

1/3x-(+3/2x)+4=0

We get rid of parentheses

1/3x-3/2x+4=0

We calculate fractions


2x/6x^2+(-9x)/6x^2+4=0

We multiply all the terms by the denominator


2x+(-9x)+4*6x^2=0

Wy multiply elements

24x^2+2x+(-9x)=0

We get rid of parentheses

24x^2+2x-9x=0

We add all the numbers together, and all the variables

24x^2-7x=0

a = 24; b = -7; c = 0;
Δ = b2-4ac
Δ = -72-4·24·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-7}{2*24}=\frac{0}{48}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+7}{2*24}=\frac{14}{48}
=7/24
$