1/3x+6=1/4(4x+10

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Solution for 1/3x+6=1/4(4x+10 equation: 



1/3x+6=1/4(4x+10

We move all terms to the left:

1/3x+6-(1/4(4x+10)=0



Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R





Domain of the equation: 4(4x+10)+6!=0

We move all terms containing x to the left, all other terms to the right

4(4x+10)!=-6

x∈R



We calculate fractions


(4x(4+6)/(12x^2(4+6)+(-(1*3x)/(12x^2(4+6)=0



We calculate terms in parentheses: +(4x(4+6)/(12x^2(4+6)+(-(1*3x)/(12x^2(4+6), so:

4x(4+6)/(12x^2(4+6)+(-(1*3x)/(12x^2(4+6

We can not solve this equation

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