1/3x+x=1500

Solution for 1/3x+x=1500 equation:

1/3x+x=1500

We move all terms to the left:

1/3x+x-(1500)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R


We add all the numbers together, and all the variables

x+1/3x-1500=0

We multiply all the terms by the denominator


x*3x-1500*3x+1=0

Wy multiply elements

3x^2-4500x+1=0

a = 3; b = -4500; c = +1;
Δ = b2-4ac
Δ = -45002-4·3·1
Δ = 20249988
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{20249988}=\sqrt{4*5062497}=\sqrt{4}*\sqrt{5062497}=2\sqrt{5062497}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4500)-2\sqrt{5062497}}{2*3}=\frac{4500-2\sqrt{5062497}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4500)+2\sqrt{5062497}}{2*3}=\frac{4500+2\sqrt{5062497}}{6}
$