1/3x+x=208

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Solution for 1/3x+x=208 equation:



1/3x+x=208
We move all terms to the left:
1/3x+x-(208)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
We add all the numbers together, and all the variables
x+1/3x-208=0
We multiply all the terms by the denominator
x*3x-208*3x+1=0
Wy multiply elements
3x^2-624x+1=0
a = 3; b = -624; c = +1;
Δ = b2-4ac
Δ = -6242-4·3·1
Δ = 389364
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{389364}=\sqrt{4*97341}=\sqrt{4}*\sqrt{97341}=2\sqrt{97341}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-624)-2\sqrt{97341}}{2*3}=\frac{624-2\sqrt{97341}}{6} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-624)+2\sqrt{97341}}{2*3}=\frac{624+2\sqrt{97341}}{6} $

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