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1/3x-(9+2/3)=22-5x
We move all terms to the left:
1/3x-(9+2/3)-(22-5x)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
1/3x-(-5x+22)-(2/3+9)=0
We get rid of parentheses
1/3x+5x-22-9-2/3=0
We calculate fractions
5x-22-9=0
We add all the numbers together, and all the variables
5x-31=0
We move all terms containing x to the left, all other terms to the right
5x=31
x=31/5
x=6+1/5
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