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1/3x-1/2+5/6x=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 6x!=0We calculate fractions
x!=0/6
x!=0
x∈R
(-108x^2)/72x^2+24x/72x^2+60x/72x^2=0
We multiply all the terms by the denominator
(-108x^2)+24x+60x=0
We add all the numbers together, and all the variables
(-108x^2)+84x=0
We get rid of parentheses
-108x^2+84x=0
a = -108; b = 84; c = 0;
Δ = b2-4ac
Δ = 842-4·(-108)·0
Δ = 7056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{7056}=84$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(84)-84}{2*-108}=\frac{-168}{-216} =7/9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(84)+84}{2*-108}=\frac{0}{-216} =0 $
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