1/3x-1/2=18(1/2)

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Solution for 1/3x-1/2=18(1/2) equation:



1/3x-1/2=18(1/2)
We move all terms to the left:
1/3x-1/2-(18(1/2))=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
We add all the numbers together, and all the variables
1/3x-1/2-(18(+1/2))=0
We calculate fractions
()/24x^2+(-3x)/24x^2+(-(18(+1*3x)/24x^2=0
We multiply all the terms by the denominator
(-3x)+(-(18(+1*3x)+()=0
We calculate terms in parentheses: +(-(18(+1*3x)+(), so:
-(18(+1*3x)+(
We get rid of parentheses
-3x+(-(18(+1*3x)+()=0
We calculate terms in parentheses: +(-(18(+1*3x)+(), so:
-(18(+1*3x)+(
We calculate terms in parentheses: +(-(18(+1*3x)+(), so:
-(18(+1*3x)+(
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-(18(+1*3x)+(
We calculate terms in parentheses: +(-(18(+1*3x)+(), so:
-(18(+1*3x)+(
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-(18(+1*3x)+(
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