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1/3x-1/5x=3
We move all terms to the left:
1/3x-1/5x-(3)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 5x!=0We calculate fractions
x!=0/5
x!=0
x∈R
5x/15x^2+(-3x)/15x^2-3=0
We multiply all the terms by the denominator
5x+(-3x)-3*15x^2=0
Wy multiply elements
-45x^2+5x+(-3x)=0
We get rid of parentheses
-45x^2+5x-3x=0
We add all the numbers together, and all the variables
-45x^2+2x=0
a = -45; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·(-45)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*-45}=\frac{-4}{-90} =2/45 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*-45}=\frac{0}{-90} =0 $
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