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1/3x-10=3/5x
We move all terms to the left:
1/3x-10-(3/5x)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 5x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
1/3x-(+3/5x)-10=0
We get rid of parentheses
1/3x-3/5x-10=0
We calculate fractions
5x/15x^2+(-9x)/15x^2-10=0
We multiply all the terms by the denominator
5x+(-9x)-10*15x^2=0
Wy multiply elements
-150x^2+5x+(-9x)=0
We get rid of parentheses
-150x^2+5x-9x=0
We add all the numbers together, and all the variables
-150x^2-4x=0
a = -150; b = -4; c = 0;
Δ = b2-4ac
Δ = -42-4·(-150)·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16}=4$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4}{2*-150}=\frac{0}{-300} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4}{2*-150}=\frac{8}{-300} =-2/75 $
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