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1/3x-15=12+1x
We move all terms to the left:
1/3x-15-(12+1x)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
1/3x-(x+12)-15=0
We get rid of parentheses
1/3x-x-12-15=0
We multiply all the terms by the denominator
-x*3x-12*3x-15*3x+1=0
Wy multiply elements
-3x^2-36x-45x+1=0
We add all the numbers together, and all the variables
-3x^2-81x+1=0
a = -3; b = -81; c = +1;
Δ = b2-4ac
Δ = -812-4·(-3)·1
Δ = 6573
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-81)-\sqrt{6573}}{2*-3}=\frac{81-\sqrt{6573}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-81)+\sqrt{6573}}{2*-3}=\frac{81+\sqrt{6573}}{-6} $
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