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1/3x-15=x-5
We move all terms to the left:
1/3x-15-(x-5)=0
Domain of the equation: 3x!=0We get rid of parentheses
x!=0/3
x!=0
x∈R
1/3x-x+5-15=0
We multiply all the terms by the denominator
-x*3x+5*3x-15*3x+1=0
Wy multiply elements
-3x^2+15x-45x+1=0
We add all the numbers together, and all the variables
-3x^2-30x+1=0
a = -3; b = -30; c = +1;
Δ = b2-4ac
Δ = -302-4·(-3)·1
Δ = 912
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{912}=\sqrt{16*57}=\sqrt{16}*\sqrt{57}=4\sqrt{57}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-4\sqrt{57}}{2*-3}=\frac{30-4\sqrt{57}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+4\sqrt{57}}{2*-3}=\frac{30+4\sqrt{57}}{-6} $
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