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1/3x-1=1/2x
We move all terms to the left:
1/3x-1-(1/2x)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
1/3x-(+1/2x)-1=0
We get rid of parentheses
1/3x-1/2x-1=0
We calculate fractions
2x/6x^2+(-3x)/6x^2-1=0
We multiply all the terms by the denominator
2x+(-3x)-1*6x^2=0
Wy multiply elements
-6x^2+2x+(-3x)=0
We get rid of parentheses
-6x^2+2x-3x=0
We add all the numbers together, and all the variables
-6x^2-1x=0
a = -6; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·(-6)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*-6}=\frac{0}{-12} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*-6}=\frac{2}{-12} =-1/6 $
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