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1/3x-2=7-9/2x
We move all terms to the left:
1/3x-2-(7-9/2x)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
1/3x-(-9/2x+7)-2=0
We get rid of parentheses
1/3x+9/2x-7-2=0
We calculate fractions
2x/6x^2+27x/6x^2-7-2=0
We add all the numbers together, and all the variables
2x/6x^2+27x/6x^2-9=0
We multiply all the terms by the denominator
2x+27x-9*6x^2=0
We add all the numbers together, and all the variables
29x-9*6x^2=0
Wy multiply elements
-54x^2+29x=0
a = -54; b = 29; c = 0;
Δ = b2-4ac
Δ = 292-4·(-54)·0
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{841}=29$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-29}{2*-54}=\frac{-58}{-108} =29/54 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+29}{2*-54}=\frac{0}{-108} =0 $
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