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1/3x-6=-1/6x-1
We move all terms to the left:
1/3x-6-(-1/6x-1)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 6x-1)!=0We get rid of parentheses
x∈R
1/3x+1/6x+1-6=0
We calculate fractions
6x/18x^2+3x/18x^2+1-6=0
We add all the numbers together, and all the variables
6x/18x^2+3x/18x^2-5=0
We multiply all the terms by the denominator
6x+3x-5*18x^2=0
We add all the numbers together, and all the variables
9x-5*18x^2=0
Wy multiply elements
-90x^2+9x=0
a = -90; b = 9; c = 0;
Δ = b2-4ac
Δ = 92-4·(-90)·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-9}{2*-90}=\frac{-18}{-180} =1/10 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+9}{2*-90}=\frac{0}{-180} =0 $
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