1/3x-6=1/8x-4

Solution for 1/3x-6=1/8x-4 equation:

1/3x-6=1/8x-4

We move all terms to the left:

1/3x-6-(1/8x-4)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R



Domain of the equation: 8x-4)!=0

x∈R


We get rid of parentheses

1/3x-1/8x+4-6=0

We calculate fractions


8x/24x^2+(-3x)/24x^2+4-6=0

We add all the numbers together, and all the variables

8x/24x^2+(-3x)/24x^2-2=0

We multiply all the terms by the denominator


8x+(-3x)-2*24x^2=0

Wy multiply elements

-48x^2+8x+(-3x)=0

We get rid of parentheses

-48x^2+8x-3x=0

We add all the numbers together, and all the variables

-48x^2+5x=0

a = -48; b = 5; c = 0;
Δ = b2-4ac
Δ = 52-4·(-48)·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-5}{2*-48}=\frac{-10}{-96}
=5/48
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+5}{2*-48}=\frac{0}{-96}
=0
$