1/3x-6=2x-27

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Solution for 1/3x-6=2x-27 equation:



1/3x-6=2x-27
We move all terms to the left:
1/3x-6-(2x-27)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
We get rid of parentheses
1/3x-2x+27-6=0
We multiply all the terms by the denominator
-2x*3x+27*3x-6*3x+1=0
Wy multiply elements
-6x^2+81x-18x+1=0
We add all the numbers together, and all the variables
-6x^2+63x+1=0
a = -6; b = 63; c = +1;
Δ = b2-4ac
Δ = 632-4·(-6)·1
Δ = 3993
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{3993}=\sqrt{121*33}=\sqrt{121}*\sqrt{33}=11\sqrt{33}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(63)-11\sqrt{33}}{2*-6}=\frac{-63-11\sqrt{33}}{-12} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(63)+11\sqrt{33}}{2*-6}=\frac{-63+11\sqrt{33}}{-12} $

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