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1/3x-8=12-1x
We move all terms to the left:
1/3x-8-(12-1x)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
1/3x-(-1x+12)-8=0
We get rid of parentheses
1/3x+1x-12-8=0
We multiply all the terms by the denominator
1x*3x-12*3x-8*3x+1=0
Wy multiply elements
3x^2-36x-24x+1=0
We add all the numbers together, and all the variables
3x^2-60x+1=0
a = 3; b = -60; c = +1;
Δ = b2-4ac
Δ = -602-4·3·1
Δ = 3588
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3588}=\sqrt{4*897}=\sqrt{4}*\sqrt{897}=2\sqrt{897}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-2\sqrt{897}}{2*3}=\frac{60-2\sqrt{897}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+2\sqrt{897}}{2*3}=\frac{60+2\sqrt{897}}{6} $
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