1/3x-8=12-3x

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Solution for 1/3x-8=12-3x equation:



1/3x-8=12-3x
We move all terms to the left:
1/3x-8-(12-3x)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
We add all the numbers together, and all the variables
1/3x-(-3x+12)-8=0
We get rid of parentheses
1/3x+3x-12-8=0
We multiply all the terms by the denominator
3x*3x-12*3x-8*3x+1=0
Wy multiply elements
9x^2-36x-24x+1=0
We add all the numbers together, and all the variables
9x^2-60x+1=0
a = 9; b = -60; c = +1;
Δ = b2-4ac
Δ = -602-4·9·1
Δ = 3564
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{3564}=\sqrt{324*11}=\sqrt{324}*\sqrt{11}=18\sqrt{11}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-18\sqrt{11}}{2*9}=\frac{60-18\sqrt{11}}{18} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+18\sqrt{11}}{2*9}=\frac{60+18\sqrt{11}}{18} $

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