1/3x-9=14x-7+3x

Solution for 1/3x-9=14x-7+3x equation:

1/3x-9=14x-7+3x

We move all terms to the left:

1/3x-9-(14x-7+3x)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R


We add all the numbers together, and all the variables

1/3x-(17x-7)-9=0

We get rid of parentheses

1/3x-17x+7-9=0

We multiply all the terms by the denominator


-17x*3x+7*3x-9*3x+1=0

Wy multiply elements

-51x^2+21x-27x+1=0

We add all the numbers together, and all the variables

-51x^2-6x+1=0

a = -51; b = -6; c = +1;
Δ = b2-4ac
Δ = -62-4·(-51)·1
Δ = 240
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{240}=\sqrt{16*15}=\sqrt{16}*\sqrt{15}=4\sqrt{15}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-4\sqrt{15}}{2*-51}=\frac{6-4\sqrt{15}}{-102}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+4\sqrt{15}}{2*-51}=\frac{6+4\sqrt{15}}{-102}
$