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1/3x-9=7(2x-1)-13x
We move all terms to the left:
1/3x-9-(7(2x-1)-13x)=0
Domain of the equation: 3x!=0We multiply all the terms by the denominator
x!=0/3
x!=0
x∈R
-((7(2x-1)-13x))*3x-9*3x+1=0
Wy multiply elements
-((7(2x-1)-13x))*3x-27x+1=0
We add all the numbers together, and all the variables
-27x-((7(2x-1)-13x))*3x+1=0
We move all terms containing x to the left, all other terms to the right
-27x-((7(2x-1)-13x))*3x=-1
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