1/3x=-22+x

Solution for 1/3x=-22+x equation:

1/3x=-22+x

We move all terms to the left:

1/3x-(-22+x)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R


We add all the numbers together, and all the variables

1/3x-(x-22)=0

We get rid of parentheses

1/3x-x+22=0

We multiply all the terms by the denominator


-x*3x+22*3x+1=0

Wy multiply elements

-3x^2+66x+1=0

a = -3; b = 66; c = +1;
Δ = b2-4ac
Δ = 662-4·(-3)·1
Δ = 4368
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4368}=\sqrt{16*273}=\sqrt{16}*\sqrt{273}=4\sqrt{273}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(66)-4\sqrt{273}}{2*-3}=\frac{-66-4\sqrt{273}}{-6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(66)+4\sqrt{273}}{2*-3}=\frac{-66+4\sqrt{273}}{-6}
$