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1/3x=1/7(184-x)=8
We move all terms to the left:
1/3x-(1/7(184-x))=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 7(184-x))!=0We add all the numbers together, and all the variables
x∈R
1/3x-(1/7(-1x+184))=0
We calculate fractions
(7x(-)/(21x^2(-)+(-(1*3x)/(21x^2(-)=0
We calculate terms in parentheses: +(7x(-)/(21x^2(-)+(-(1*3x)/(21x^2(-), so:
7x(-)/(21x^2(-)+(-(1*3x)/(21x^2(-
We can not solve this equation
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