1/3x=2-x

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Solution for 1/3x=2-x equation:



1/3x=2-x
We move all terms to the left:
1/3x-(2-x)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
We add all the numbers together, and all the variables
1/3x-(-1x+2)=0
We get rid of parentheses
1/3x+1x-2=0
We multiply all the terms by the denominator
1x*3x-2*3x+1=0
Wy multiply elements
3x^2-6x+1=0
a = 3; b = -6; c = +1;
Δ = b2-4ac
Δ = -62-4·3·1
Δ = 24
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{24}=\sqrt{4*6}=\sqrt{4}*\sqrt{6}=2\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2\sqrt{6}}{2*3}=\frac{6-2\sqrt{6}}{6} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2\sqrt{6}}{2*3}=\frac{6+2\sqrt{6}}{6} $

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