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1/3x=22x
We move all terms to the left:
1/3x-(22x)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
-22x+1/3x=0
We multiply all the terms by the denominator
-22x*3x+1=0
Wy multiply elements
-66x^2+1=0
a = -66; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·(-66)·1
Δ = 264
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{264}=\sqrt{4*66}=\sqrt{4}*\sqrt{66}=2\sqrt{66}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{66}}{2*-66}=\frac{0-2\sqrt{66}}{-132} =-\frac{2\sqrt{66}}{-132} =-\frac{\sqrt{66}}{-66} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{66}}{2*-66}=\frac{0+2\sqrt{66}}{-132} =\frac{2\sqrt{66}}{-132} =\frac{\sqrt{66}}{-66} $
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