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1/3x=2x+15
We move all terms to the left:
1/3x-(2x+15)=0
Domain of the equation: 3x!=0We get rid of parentheses
x!=0/3
x!=0
x∈R
1/3x-2x-15=0
We multiply all the terms by the denominator
-2x*3x-15*3x+1=0
Wy multiply elements
-6x^2-45x+1=0
a = -6; b = -45; c = +1;
Δ = b2-4ac
Δ = -452-4·(-6)·1
Δ = 2049
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45)-\sqrt{2049}}{2*-6}=\frac{45-\sqrt{2049}}{-12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45)+\sqrt{2049}}{2*-6}=\frac{45+\sqrt{2049}}{-12} $
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