1/3x=2x+5

Solution for 1/3x=2x+5 equation:

1/3x=2x+5

We move all terms to the left:

1/3x-(2x+5)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R


We get rid of parentheses

1/3x-2x-5=0

We multiply all the terms by the denominator


-2x*3x-5*3x+1=0

Wy multiply elements

-6x^2-15x+1=0

a = -6; b = -15; c = +1;
Δ = b2-4ac
Δ = -152-4·(-6)·1
Δ = 249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-\sqrt{249}}{2*-6}=\frac{15-\sqrt{249}}{-12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+\sqrt{249}}{2*-6}=\frac{15+\sqrt{249}}{-12}
$