1/3x=2x+50

Solution for 1/3x=2x+50 equation:

1/3x=2x+50

We move all terms to the left:

1/3x-(2x+50)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R


We get rid of parentheses

1/3x-2x-50=0

We multiply all the terms by the denominator


-2x*3x-50*3x+1=0

Wy multiply elements

-6x^2-150x+1=0

a = -6; b = -150; c = +1;
Δ = b2-4ac
Δ = -1502-4·(-6)·1
Δ = 22524
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{22524}=\sqrt{4*5631}=\sqrt{4}*\sqrt{5631}=2\sqrt{5631}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-150)-2\sqrt{5631}}{2*-6}=\frac{150-2\sqrt{5631}}{-12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-150)+2\sqrt{5631}}{2*-6}=\frac{150+2\sqrt{5631}}{-12}
$