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1/3x=x-24
We move all terms to the left:
1/3x-(x-24)=0
Domain of the equation: 3x!=0We get rid of parentheses
x!=0/3
x!=0
x∈R
1/3x-x+24=0
We multiply all the terms by the denominator
-x*3x+24*3x+1=0
Wy multiply elements
-3x^2+72x+1=0
a = -3; b = 72; c = +1;
Δ = b2-4ac
Δ = 722-4·(-3)·1
Δ = 5196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{5196}=\sqrt{4*1299}=\sqrt{4}*\sqrt{1299}=2\sqrt{1299}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(72)-2\sqrt{1299}}{2*-3}=\frac{-72-2\sqrt{1299}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(72)+2\sqrt{1299}}{2*-3}=\frac{-72+2\sqrt{1299}}{-6} $
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