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1/3y+1/5y=5/3
We move all terms to the left:
1/3y+1/5y-(5/3)=0
Domain of the equation: 3y!=0
y!=0/3
y!=0
y∈R
Domain of the equation: 5y!=0We add all the numbers together, and all the variables
y!=0/5
y!=0
y∈R
1/3y+1/5y-(+5/3)=0
We get rid of parentheses
1/3y+1/5y-5/3=0
We calculate fractions
5y/135y^2+27y/135y^2+(-25y)/135y^2=0
We multiply all the terms by the denominator
5y+27y+(-25y)=0
We add all the numbers together, and all the variables
32y+(-25y)=0
We get rid of parentheses
32y-25y=0
We add all the numbers together, and all the variables
7y=0
y=0/7
y=0
Równanie nie ma rozwiązania
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