1/3y+11=1/2y+3

Solution for 1/3y+11=1/2y+3 equation:

1/3y+11=1/2y+3

We move all terms to the left:

1/3y+11-(1/2y+3)=0


Domain of the equation: 3y!=0

y!=0/3

y!=0

y∈R



Domain of the equation: 2y+3)!=0

y∈R


We get rid of parentheses

1/3y-1/2y-3+11=0

We calculate fractions


2y/6y^2+(-3y)/6y^2-3+11=0

We add all the numbers together, and all the variables

2y/6y^2+(-3y)/6y^2+8=0

We multiply all the terms by the denominator


2y+(-3y)+8*6y^2=0

Wy multiply elements

48y^2+2y+(-3y)=0

We get rid of parentheses

48y^2+2y-3y=0

We add all the numbers together, and all the variables

48y^2-1y=0

a = 48; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·48·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*48}=\frac{0}{96}
=0
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*48}=\frac{2}{96}
=1/48
$