1/3y-4/3=1/6(y-12)

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Solution for 1/3y-4/3=1/6(y-12) equation: 



1/3y-4/3=1/6(y-12)

We move all terms to the left:

1/3y-4/3-(1/6(y-12))=0



Domain of the equation: 3y!=0

y!=0/3

y!=0

y∈R





Domain of the equation: 6(y-12))!=0

y∈R



We calculate fractions


(6yy/(54y^2y+(-(1*3y*3)/(54y^2y+(-24yy/(54y^2y=0

We can not solve this equation

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