1/3y=(2x-x)(4x-x)

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Solution for 1/3y=(2x-x)(4x-x) equation: 


x in (-oo:+oo)

(1/3)*y = (2*x-x)*(4*x-x) // - (2*x-x)*(4*x-x)

(1/3)*y-((2*x-x)*(4*x-x)) = 0

y/3-1*3*x*x = 0

(-1*3*3*x*x)/3+y/3 = 0

y-1*3*3*x*x = 0

y-9*x^2 = 0

(y-9*x^2)/3 = 0

(y-9*x^2)/3 = 0 // * 3

y-9*x^2 = 0

-9*x^2 = -y // : -9

x^2 = y/9

x^2 = y/9 // ^ 1/2

abs(x) = (y^(1/2))/3

x = (y^(1/2))/3 or x = -((y^(1/2))/3)

x in { (y^(1/2))/3, -((y^(1/2))/3) }

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