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1/3z+1/5z=3/5
We move all terms to the left:
1/3z+1/5z-(3/5)=0
Domain of the equation: 3z!=0
z!=0/3
z!=0
z∈R
Domain of the equation: 5z!=0We add all the numbers together, and all the variables
z!=0/5
z!=0
z∈R
1/3z+1/5z-(+3/5)=0
We get rid of parentheses
1/3z+1/5z-3/5=0
We calculate fractions
125z/375z^2+3z/375z^2+(-9z)/375z^2=0
We multiply all the terms by the denominator
125z+3z+(-9z)=0
We add all the numbers together, and all the variables
128z+(-9z)=0
We get rid of parentheses
128z-9z=0
We add all the numbers together, and all the variables
119z=0
z=0/119
z=0
Równanie nie ma rozwiązania
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