1/3z+3=4-z

Solution for 1/3z+3=4-z equation:

1/3z+3=4-z

We move all terms to the left:

1/3z+3-(4-z)=0


Domain of the equation: 3z!=0

z!=0/3

z!=0

z∈R


We add all the numbers together, and all the variables

1/3z-(-1z+4)+3=0

We get rid of parentheses

1/3z+1z-4+3=0

We multiply all the terms by the denominator


1z*3z-4*3z+3*3z+1=0

Wy multiply elements

3z^2-12z+9z+1=0

We add all the numbers together, and all the variables

3z^2-3z+1=0

a = 3; b = -3; c = +1;
Δ = b2-4ac
Δ = -32-4·3·1
Δ = -3
Delta is less than zero, so there is no solution for the equation