1/3z+6=12

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Solution for 1/3z+6=12 equation: 



1/3z+6=12

We move all terms to the left:

1/3z+6-(12)=0



Domain of the equation: 3z!=0

z!=0/3

z!=0

z∈R



We add all the numbers together, and all the variables

1/3z-6=0

We multiply all the terms by the denominator


-6*3z+1=0

Wy multiply elements

-18z+1=0

We move all terms containing z to the left, all other terms to the right

-18z=-1

z=-1/-18

z=1/18

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