1/3z+6=3/2(z+6)

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Solution for 1/3z+6=3/2(z+6) equation: 



1/3z+6=3/2(z+6)

We move all terms to the left:

1/3z+6-(3/2(z+6))=0



Domain of the equation: 3z!=0

z!=0/3

z!=0

z∈R





Domain of the equation: 2(z+6))!=0

z∈R



We calculate fractions


(2zz/(6z^2z+(-(3*3z)/(6z^2z+6=0

We can not solve this equation

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