1/3z+6=33

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Solution for 1/3z+6=33 equation:



1/3z+6=33
We move all terms to the left:
1/3z+6-(33)=0
Domain of the equation: 3z!=0
z!=0/3
z!=0
z∈R
We add all the numbers together, and all the variables
1/3z-27=0
We multiply all the terms by the denominator
-27*3z+1=0
Wy multiply elements
-81z+1=0
We move all terms containing z to the left, all other terms to the right
-81z=-1
z=-1/-81
z=1/81

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