1/4((2k+1)*(2k+1)+3)=2k+1

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Solution for 1/4((2k+1)*(2k+1)+3)=2k+1 equation: 



1/4((2k+1)(2k+1)+3)=2k+1

We move all terms to the left:

1/4((2k+1)(2k+1)+3)-(2k+1)=0



Domain of the equation: 4((2k+1)(2k+1)+3)!=0

k∈R



We get rid of parentheses

1/4((2k+1)(2k+1)+3)-2k-1=0

We multiply parentheses ..

1/4((+4k^2+2k+2k+1)+3)-2k-1=0

We multiply all the terms by the denominator


-2k*4((+4k^2+2k+2k+1)+3)-1*4((+4k^2+2k+2k+1)+3)+1=0

Wy multiply elements

-8k^2((-4k((+1=0

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