1/4(-12k+40)=6+12k

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Solution for 1/4(-12k+40)=6+12k equation: 



1/4(-12k+40)=6+12k

We move all terms to the left:

1/4(-12k+40)-(6+12k)=0



Domain of the equation: 4(-12k+40)!=0

k∈R



We add all the numbers together, and all the variables

1/4(-12k+40)-(12k+6)=0

We get rid of parentheses

1/4(-12k+40)-12k-6=0

We multiply all the terms by the denominator


-12k*4(-12k+40)-6*4(-12k+40)+1=0

Wy multiply elements

-48k^2(--24k(-+1=0

We use the square of the difference formula

-48k^2(+24k(-1=0

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