1/4(-3n+4)=7/12(-6n-3)

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Solution for 1/4(-3n+4)=7/12(-6n-3) equation: 



1/4(-3n+4)=7/12(-6n-3)

We move all terms to the left:

1/4(-3n+4)-(7/12(-6n-3))=0



Domain of the equation: 4(-3n+4)!=0

n∈R





Domain of the equation: 12(-6n-3))!=0

n∈R



We calculate fractions


(12n(-)/(4(-3n+4)*12(-6n-3)))+(-28n0/(4(-3n+4)*12(-6n-3)))=0



We calculate terms in parentheses: +(12n(-)/(4(-3n+4)*12(-6n-3))), so:

12n(-)/(4(-3n+4)*12(-6n-3))

We add all the numbers together, and all the variables

12n0/(4(-3n+4)*12(-6n-3))

We multiply all the terms by the denominator


12n0

We add all the numbers together, and all the variables

12n

Back to the equation:

+(12n)





We calculate terms in parentheses: +(-28n0/(4(-3n+4)*12(-6n-3))), so:

-28n0/(4(-3n+4)*12(-6n-3))

We multiply all the terms by the denominator


-28n0

We add all the numbers together, and all the variables

-28n

Back to the equation:

+(-28n)



We get rid of parentheses

12n-28n=0

We add all the numbers together, and all the variables

-16n=0

n=0/-16

n=0

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