1/4(1-x)=3/4(1+x)

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Solution for 1/4(1-x)=3/4(1+x) equation: 



1/4(1-x)=3/4(1+x)

We move all terms to the left:

1/4(1-x)-(3/4(1+x))=0



Domain of the equation: 4(1-x)!=0

x∈R





Domain of the equation: 4(1+x))!=0

x∈R



We add all the numbers together, and all the variables

1/4(-1x+1)-(3/4(x+1))=0

We calculate fractions


(4xx/(4(-1x+1)*4(x+1)))+(-12x0/(4(-1x+1)*4(x+1)))=0



We calculate terms in parentheses: +(4xx/(4(-1x+1)*4(x+1))), so:

4xx/(4(-1x+1)*4(x+1))

We multiply all the terms by the denominator


4xx

Back to the equation:

+(4xx)





We calculate terms in parentheses: +(-12x0/(4(-1x+1)*4(x+1))), so:

-12x0/(4(-1x+1)*4(x+1))

We multiply all the terms by the denominator


-12x0

We add all the numbers together, and all the variables

-12x

Back to the equation:

+(-12x)



We get rid of parentheses

4xx-12x=0

We add all the numbers together, and all the variables

-12x+4xx=0

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