1/4(10x+12)=(9-12x)1/3

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Solution for 1/4(10x+12)=(9-12x)1/3 equation: 


x in (-oo:+oo)

(1/4)*(10*x+12) = ((9-(12*x))^1)/3 // - ((9-(12*x))^1)/3

(1/4)*(10*x+12)-(((9-(12*x))^1)/3) = 0

(1/4)*(10*x+12)-((9-12*x)/3) = 0

1/4*(10*x+12)+(-1*(9-12*x))/3 = 0

(1/4*3*(10*x+12))/3+(-1*(9-12*x))/3 = 0

1/4*3*(10*x+12)-1*(9-12*x) = 0

39/2*x = 0

(39/2*x)/3 = 0

(39/2*x)/3 = 0 // * 3

(39*x)/2 = 0

39/2*x = 0 // : 39/2

x = 0

x = 0

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