1/4(12+16)=10-3(x-2)

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Solution for 1/4(12+16)=10-3(x-2) equation: 



1/4(12+16)=10-3(x-2)

We move all terms to the left:

1/4(12+16)-(10-3(x-2))=0

We add all the numbers together, and all the variables

-(10-3(x-2))+1/428=0

We multiply all the terms by the denominator


-((10-3(x-2)))*428+1=0

We move all terms containing x to the left, all other terms to the right

-((10-3(x-2)))*428=-1

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