1/4(12-20x)=3+5x

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Solution for 1/4(12-20x)=3+5x equation: 



1/4(12-20x)=3+5x

We move all terms to the left:

1/4(12-20x)-(3+5x)=0



Domain of the equation: 4(12-20x)!=0

x∈R



We add all the numbers together, and all the variables

1/4(-20x+12)-(5x+3)=0

We get rid of parentheses

1/4(-20x+12)-5x-3=0

We multiply all the terms by the denominator


-5x*4(-20x+12)-3*4(-20x+12)+1=0

Wy multiply elements

-20x^2(--12x(-+1=0

We use the square of the difference formula

-20x^2(+12x(-1=0

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