1/4(12a-28)=-1/3(21-9a)

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Solution for 1/4(12a-28)=-1/3(21-9a) equation:



1/4(12a-28)=-1/3(21-9a)
We move all terms to the left:
1/4(12a-28)-(-1/3(21-9a))=0
Domain of the equation: 4(12a-28)!=0
a∈R
Domain of the equation: 3(21-9a))!=0
a∈R
We add all the numbers together, and all the variables
1/4(12a-28)-(-1/3(-9a+21))=0
We calculate fractions
(3a(-)/(4(12a-28)*3(-9a+21)))+(-(-4a1)/(4(12a-28)*3(-9a+21)))=0
We calculate terms in parentheses: +(3a(-)/(4(12a-28)*3(-9a+21))), so:
3a(-)/(4(12a-28)*3(-9a+21))
We add all the numbers together, and all the variables
3a0/(4(12a-28)*3(-9a+21))
We multiply all the terms by the denominator
3a0
We add all the numbers together, and all the variables
3a
Back to the equation:
+(3a)
We calculate terms in parentheses: +(-(-4a1)/(4(12a-28)*3(-9a+21))), so:
-(-4a1)/(4(12a-28)*3(-9a+21))
We add all the numbers together, and all the variables
-(-4a)/(4(12a-28)*3(-9a+21))
We multiply all the terms by the denominator
-(-4a)
We get rid of parentheses
4a
Back to the equation:
+(4a)
We add all the numbers together, and all the variables
7a=0
a=0/7
a=0

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